old sm SVF filter - anyone knows the hz to cutoff formula?

DSP related issues, mathematics, processing and techniques
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MichaelBenjamin
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Joined: Tue Jul 13, 2010 1:32 pm

old sm SVF filter - anyone knows the hz to cutoff formula?

Post by MichaelBenjamin »

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Last edited by MichaelBenjamin on Mon Sep 21, 2020 10:30 am, edited 1 time in total.
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martinvicanek
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Re: old sm SVF filter - anyone knows the hz to cutoff formul

Post by martinvicanek »

Corner frequency in Hz is roughly equal to samplerate*cutoff/2pi. But that's only valid for low cutoffs. For higher cutoffs the filter becomes weird and even unstable.

There is an SVF implementation which goes all the way up to Nyquist, search the forum for ZDF (zero delay feedback) filter.
MichaelBenjamin
Posts: 275
Joined: Tue Jul 13, 2010 1:32 pm

Re: old sm SVF filter - anyone knows the hz to cutoff formul

Post by MichaelBenjamin »

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Last edited by MichaelBenjamin on Mon Sep 21, 2020 10:30 am, edited 1 time in total.
tulamide
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Re: old sm SVF filter - anyone knows the hz to cutoff formul

Post by tulamide »

martinvicanek wrote:Corner frequency in Hz is roughly equal to samplerate*cutoff/2pi. But that's only valid for low cutoffs. For higher cutoffs the filter becomes weird and even unstable.

There is an SVF implementation which goes all the way up to Nyquist, search the forum for ZDF (zero delay feedback) filter.

I understand that it has been solved otherwise. But I try to understand the answer.

sample rate = 44.1kHz
cutoff = 0.5

corner frequency = (roughly) 3500 Hz

But the user shall enter the cutoff as a frequency
cf = sr * c / 2pi
cf * 2pi = sr * c
c = cf * 2pi /sr (?)
I don't know cf, when user enters a cutoff of say 7000 Hz

I'm sure it's something simple that I don't see or messed up.
"There lies the dog buried" (German saying translated literally)
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